day 1

1a.py

# find the two entries that sum to 2020 and then multiply those two numbers together
# input
with open('1.txt', 'r') as file:
    input = file.read()
# turn the input into a list
list_str = list(input.split('\n'))
# get a list of ints
list_int = []
for k in list_str:
    list_int.append(int(k))
# find the pair and multiply them
for i in list_int:
    for j in list_int:
        if i + j == 2020:
            print(i*j)

1b.py

# find the three entries that sum to 2020 and then multiply those three numbers together
# input
with open('1.txt', 'r') as file:
    input = file.read()
# turn the input into a list
list_str = list(input.split('\n'))
# get a list of ints
list_int = []
for k in list_str:
    list_int.append(int(k))
# find the pair and multiply them
for i in list_int:
    for j in list_int:
        for k in list_int:
            if i + j + k == 2020:
                print(i*j*k)

this prints the correct answer multiple times since i haven't forced i,j,k to be distinct, but i don't really care seeing as i got the correct answer lol